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Wind strength differs between sun & shaded areas

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Created by sausage > 9 months ago, 4 Apr 2014
paddymac
WA, 939 posts
5 Apr 2014 8:22PM
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Not the scientific response but...

In WA many sailors note that summer easterlies (coming off warm land) do not have the same power as seabreeze SW of the same wind speed. You can see the difference in gear used fairly clearly in the 15 knot range. A 15 knot easterly usually sees larger gear being used than a 15 knot seabreeze.

I always put it down to the weight of the wind, i.e. hot wind (like a summer easterly), for a given volume, would have less weight. Not sure how accurate that is looking at the maths above.

evlPanda
NSW, 9207 posts
6 Apr 2014 4:11PM
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evlPanda said..



where L is lift force, p is air density, v is true airspeed
And we don't care about the others, the foil.


A) Low pressure 980, in winter @ 5 degrees = 1.2278 kg/m3
B) High pressure 1050, in summer @ 40 degrees = 1.1684 kg/m3

Gives us

scenario A = 0.5 * 1.2278 * 20^2 = 245 wind strengths
scenario B = 0.5 * 1.1684 * 20^2 = 233 wind strengths

A 5% difference.

Which is the difference between a 6.5 and a 6.8 sail!!! Noticeable!!!
Yay maths! (I know it's probably wrong)


The difference between 980 and 1050 is about 5%, numbskull. No formula required.

sboardcrazy
NSW, 8253 posts
6 Apr 2014 6:43PM
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Select to expand quote
P.C_simpson said..

Yes a 20 knot seabreeze in Western Australia is much more powerful than on the East Coast..


i thought that was because its more consistent in wa ?

paddymac
WA, 939 posts
6 Apr 2014 9:56PM
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evlPanda said..

evlPanda said..



where L is lift force, p is air density, v is true airspeed
And we don't care about the others, the foil.


A) Low pressure 980, in winter @ 5 degrees = 1.2278 kg/m3
B) High pressure 1050, in summer @ 40 degrees = 1.1684 kg/m3

Gives us

scenario A = 0.5 * 1.2278 * 20^2 = 245 wind strengths
scenario B = 0.5 * 1.1684 * 20^2 = 233 wind strengths

A 5% difference.

Which is the difference between a 6.5 and a 6.8 sail!!! Noticeable!!!
Yay maths! (I know it's probably wrong)


The difference between 980 and 1050 is about 5%, numbskull. No formula required.


Not getting enough time on water making you grumpy?

My comparison is not between summer and winter, it is morning and afternoon on a summer day. So assume general atmospheric air pressure as a constant. What differs is temperature of the water/land the wind travels over. The hypothesis is that wind travelling over warm land, compared to travelling over cooler water, has less power. This effect must be more localised, with the hot air having lower pressure than the cool air.

Given that PV=nRT (where P is the pressure, V is the volume, n is the number of moles in the system, R is the ideal gas law constant, and T is the temperature) we can see that pressure has a linear relationship to temperature. Assuming temperature over land on a hot summer day is 40deg C (313K) and water temp is 20deg C (293K) we have a 6% difference in pressure.

I'm not sure that is enough to explain the anecdotal evidence. So there may be other factors at play. I think that the factors put forward by TGale and jaymac may be more significant.

seanhogan
QLD, 3424 posts
7 Apr 2014 10:11AM
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same here, morning/afternoon .... 5%



Fez
NSW, 130 posts
7 Apr 2014 11:08AM
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Looks like there some cracks appearing in your argument Seanhogan!

seanhogan
QLD, 3424 posts
7 Apr 2014 11:28AM
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well I was never good at maths in school....
or is it "in maths at school" ??? wasn't good in grammar also it seems !!

qldnacra
QLD, 455 posts
7 Apr 2014 12:19PM
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Or maybe the cloud just produces a sort of atmospheric Venturi and compresses the wind just a fraction more than when it has an open ski to travel through. No proof of this just a theory.

jaymac
WA, 44 posts
7 Apr 2014 10:54AM
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The real demonstration of wind shear is during a winter storm, you rig a 4.2 for the smooth water on the bay, and fly overpowered offshore. once it comes to a waterstart in a steep 4 metre waves and swell the problems begin.
The wind is howling just out of reach of a sail being held a 25 deg above the horizontal.
Anybody got any good ideas ???

Chris6791
WA, 3271 posts
7 Apr 2014 2:47PM
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Select to expand quote
SHEETIN said..

20 knots is the same strength regardless of the direction.


Only if you can negate every other variable, of which there are many.

evlPanda
NSW, 9207 posts
10 Apr 2014 1:47PM
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paddymac said..

evlPanda said..

evlPanda said..



where L is lift force, p is air density, v is true airspeed
And we don't care about the others, the foil.


A) Low pressure 980, in winter @ 5 degrees = 1.2278 kg/m3
B) High pressure 1050, in summer @ 40 degrees = 1.1684 kg/m3

Gives us

scenario A = 0.5 * 1.2278 * 20^2 = 245 wind strengths
scenario B = 0.5 * 1.1684 * 20^2 = 233 wind strengths

A 5% difference.

Which is the difference between a 6.5 and a 6.8 sail!!! Noticeable!!!
Yay maths! (I know it's probably wrong)


The difference between 980 and 1050 is about 5%, numbskull. No formula required.


Not getting enough time on water making you grumpy?


Oh man

What is it now? April? God Damn it.



Another weekend of no sailing.

sboardcrazy
NSW, 8253 posts
10 Apr 2014 2:13PM
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At least there are green arrows somewhere!

sboardcrazy
NSW, 8253 posts
10 Apr 2014 2:18PM
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Surely 20kts is 20kts?

mathew
QLD, 2136 posts
10 Apr 2014 7:31PM
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Select to expand quote
sboardcrazy said..

Surely 20kts is 20kts?


yes. but no.

I throw (I'm very strong you know)...:
- 1m-cubed of water at you at 1m/s,
- 1m-cubed of lead at you at 1m/s,
... water weighs 1 tonne, lead weighs 11 tonnes...

In the real world when we are sailing around, cold-air is more dense than warm air... aka it is heavier (thus the water/lead comparison).
"More dense" means "more air molecules" per unit volume, which means more of them to impart their force onto your sail.

Or if you like: "PV=nRT"...

P = pressure... usually reasonably constant for a given area that you will be sailing in (but not always).
V = volume... in our context, it would be the volume of air that the sail moves through... but whatever it is, it doesn't change
R = is the gas-constant... which is... a constant.
T = is the temperature
n = is the number-of-moles... aka density... aka the number of air molecules

Increase T, decrease n.
Decrease the number of air molecules, the less of them hit your sail... so less force imparted onto it.


...so while 20kn is 20kn, the colder 20kn will be more effective.

Gestalt
QLD, 14671 posts
11 Apr 2014 12:38PM
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is the relationship between t and n linear?

in the back of my mind is the idea that 20 knots is 20knots regardless because the wind with a higher density will do less work to make the wind gauge register 20 knots.

John340
QLD, 3365 posts
11 Apr 2014 1:53PM
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Select to expand quote
mathew said..

sboardcrazy said..

Surely 20kts is 20kts?


yes. but no.

I throw (I'm very strong you know)...:
- 1m-cubed of water at you at 1m/s,
- 1m-cubed of lead at you at 1m/s,
... water weighs 1 tonne, lead weighs 11 tonnes...

In the real world when we are sailing around, cold-air is more dense than warm air... aka it is heavier (thus the water/lead comparison).
"More dense" means "more air molecules" per unit volume, which means more of them to impart their force onto your sail.

Or if you like: "PV=nRT"...

P = pressure... usually reasonably constant for a given area that you will be sailing in (but not always).
V = volume... in our context, it would be the volume of air that the sail moves through... but whatever it is, it doesn't change
R = is the gas-constant... which is... a constant.
T = is the temperature
n = is the number-of-moles... aka density... aka the number of air molecules

Increase T, decrease n.
Decrease the number of air molecules, the less of them hit your sail... so less force imparted onto it.


...so while 20kn is 20kn, the colder 20kn will be more effective.


All correct, but as previously posted earlier in the thread, the temperature is measure in Kelvin. Hence if the ave temp is 30deg and the difference in temperature between shade and sun is max 5 deg Celcius, then when converted to Kelvin the difference is 300degK to 305degK which is less than 1.6%. I don't believe we could objectively feel the difference. I personnaly don't feel that the wind blows stronger in the shade unless it is actually blowing stronger like in a rain squall.

With regard to comments that WA 20knt wind is stronger than 20knt in Qld. The difference in temp between a WA SWer and Qld NEer is max 10degC. Hence the % change in temp measured in Kelvin is 3.2%. Again, I don't think we could objectively feel this

BillWiltshi
5 posts
11 Apr 2014 4:01PM
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What interests me is the difference in wind strength in relation to the temperature of the water that I'm sailing over.
Where I sail in the tropics includes a river mouth, inshore weed reefs, current lines and sea grass flats. There have been days when sailing in 15/18kts of Northerly the reefs are almost perfectly defined as calm patches. You can plane across the edge and stop,blob across then off again. I feel the wind is wedged upwards due the water temp in this situation. At other times the effect is far more subtle but still there. The wind get choppier and the micro gusts more frequent ect. Sunlight and cloud also have an effect.

evlPanda
NSW, 9207 posts
11 Apr 2014 9:18PM
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Select to expand quote
evlPanda said...

Oh man

What is it now? April? God Damn it.



Another weekend of no sailing.




Whoah.

walive
WA, 6 posts
12 Apr 2014 7:01AM
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Don't forget humidity that can alter things by as much as ummm 3% at 40c I think, ok maybe we can forget humidity



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"Wind strength differs between sun & shaded areas" started by sausage